Problem based on Age Test for IBPS PO Exam
Let x = Anita's age now.
= Difference between their ages NOW is 24-x.
24 - x years ago, Bala was a years old, while Anita was x-(24-x) = 2x - 24.
During that time, x = 2(2x-24), or x = 4x - 48, or 3x = 48, or x = 16.
Thus Anita is 16 years old now.
Ans 2. 21 years. One year from today he will be 22, and twice as old as he was 10 years ago, i.e. when he was 11.
Ans 3. 6 years
Ans 4. 38 years
Ans 5. 5 years. The difference in their ages will always remain the same.
Ans 6. 6 and 2. A = B + 4, A + 16 = 3A ⇒ A = 16 B + 16 = 5B ⇒ B = 4
∴ Ages of A and B two years before the initially indicated stage are 6 years and 2 years respectively.
Ans 7. A = 48, B = 32
Ans 8. 13
Ans 9. 35
Let B be Ravi's brother.
Let Ravi = R
∴ R + 3 = B
When sister S was born, i.e. when S = 0,
F = 28, M = 26 ....(1)
When B = 0, S = 4
When R = 0, S = 7
At this stage, F = 35 (Using (1))
Ans 10. Jyotsna
Saurabh < Richa < Sumit (= Amit) < Jyotsna
Thus Anita is 16 years old now.
Ans 2. 21 years. One year from today he will be 22, and twice as old as he was 10 years ago, i.e. when he was 11.
Ans 3. 6 years
Ans 4. 38 years
Ans 5. 5 years. The difference in their ages will always remain the same.
Ans 6. 6 and 2. A = B + 4, A + 16 = 3A ⇒ A = 16 B + 16 = 5B ⇒ B = 4
∴ Ages of A and B two years before the initially indicated stage are 6 years and 2 years respectively.
Ans 7. A = 48, B = 32
Ans 8. 13
Ans 9. 35
Let B be Ravi's brother.
Let Ravi = R
∴ R + 3 = B
When sister S was born, i.e. when S = 0,
F = 28, M = 26 ....(1)
When B = 0, S = 4
When R = 0, S = 7
At this stage, F = 35 (Using (1))
Ans 10. Jyotsna
Saurabh < Richa < Sumit (= Amit) < Jyotsna
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